If you have a problem like:
4x+2y=20
2x+2y=16
You would subtract
4x-2y=20
-2x+2y=16
You would get the new problum
2x=4
You now want to divide the 2 on both sides to solve for x
x=2
Now that you've solved for X you want to solve for y. So use substitution to solve for y. You would want to substatute the x for the 2 in either of the problums. I'll use the first one.
4(2)+2y=20
You first want to multiply te 4(2) you would get a new problum.
8+2y=20
Now you want to subtract the 8 on both sides.
2y=12
The last step to solve for y is to divide the 2 on both sides.
Y=6
So your answers would be
x=2
y=6
Answer:
Correct option: second one
Step-by-step explanation:
Let's check each option to find the correct one.
First option: x and y increase by 2.3 times, so the figure expands. So this is not the correct option.
Second option: x and y decrease 0.52 times, so the figure is reduced. So this is the correct option.
Third option: x and y are translated by 1/3 of their position, so the figure is not reduced.
Fourth option: x and y increase by 7/2 times, so the figure expands. So this is not the correct option.
Correct option: second one
We have the following equation:
<span> h(t)=-4.92t^2+17.69t+575
</span> For the domain we have:
<span> </span>We match zero:
-4.92t ^ 2 + 17.69t + 575 = 0
We look for the roots:
t1 = -9.16
t2 = 12.76
We are left with the positive root, so the domain is:
[0, 12.76]
For the range we have:
We derive the function:
h '(t) = - 9.84t + 17.69
We equal zero and clear t:
-9.84t + 17.69 = 0
t = 17.69 / 9.84
t = 1.80
We evaluate the time in which it reaches the maximum height in the function:
h (1.80) = - 4.92 * (1.80) ^ 2 + 17.69 * (1.80) +575
h (1.80) = 590.90
Therefore, the range is given by:
[0, 590.9]
Answer:
the domain and range are:
domain: [0, 12.76] range: [0, 590.9]
Answer:
See explanation below
<u>Step-by-step explanation:</u>
range = 2200 - 300 = 1900
To find standard deviation, we have:
standard deviation = range/4 = = 475
The range rule of thumb estimate for the standard deviation is 475
Given:
Standard deviation, = 475
Margin of Error, ME = 100
= 1 - 0.90 = 0.10
Za/2 = Z0.05 = 1.64
Find sample size, n:
n ≥
n ≥
n ≥ 60.68
≈ 61
Minimun sample size,n = 61
Answer:
It would be:
4 5/9 x 1/2
4 5/9 x 10/10
4 5/9 x 6
Step-by-step explanation: