Answer:
(-3, 2)
Step-by-step explanation:
{3x=7y=5
{5x-2y=-19
solve....
maybe it was 3x + 7y = 5
and 5x - 2y = -19
2*(3x + 7y = 5)
7*(5x - 2y = -19)
-------------
6x + 14y = 10
35x -14y = -133
41x = -123
x = -3
y = ...
5*(-3) - 2y = -19
-15 - 2y = -19
2y = 4
y = 2
(-3, 2)
The vertex is the high point of the curve, (2, 1). The vertex form of the equation for a parabola is
.. y = a*(x -h)^2 +k . . . . . . . for vertex = (h, k)
Using the vertex coordinates we read from the graph, the equation is
.. y = a*(x -2)^2 +1
We need to find the value of "a". We can do that by using any (x, y) value that we know (other than the vertex), for example (1, 0).
.. 0 = a*(1 -2)^2 +1
.. 0 = a*1 +1
.. -1 = a
Now we know the equation is
.. y = -(x -2)^2 +1
_____
If we like, we can expand it to
.. y = -(x^2 -4x +4) +1
.. y = -x^2 +4x -3
=========
An alternative approach would be to make use of the zeros. You can read the x-intercepts from the graph as x=1 and x=3. Then you can write the equation as
.. y = a*(x -1)*(x -3)
Once again, you need to find the value of "a" using some other point on the graph. The vertex (x, y) = (2, 1) is one such point. Subsituting those values, we get
.. 1 = a*(2 -1)*(2 -3) = a*1*-1 = -a
.. -1 = a
Then the equation of the graph can be written as
.. y = -(x -1)(x -3)
In expanded form, this is
.. y = -(x^2 -4x +3)
.. y = -x^2 +4x -3 . . . . . . same as above
Q = p(r+s)
--------------
(r+s) (r+s) Divide both sides by (r+s) so you can get the p bu itself this way you get q / (r+s) = p
The two integers that sum is 101 is 20.2 and 1
Answer:
802
Step-by-step explanation:
802
