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3 years ago

What is the y-intercept for y+2= -3/4(x+4)

Mathematics

1 answer:

fiasKO [112]3 years ago

8 0

The answer would be: -5

Heres how you solve it!

First, change the x into a 0 so it can be removed.

y+2= -3/4*4

Now with the GCF you can reduce the numbers with 4.

y+2= -3

Then move the 2 to the other side causing it to change its sign into a negative

y= -3-2

Since -3 and -2 are both negative it would be -5

y= -5

then you are left with your answer.

Hope this helps! :3

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I'm really bad at math

Lynna [10]

What chapter is this?

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2 years ago

Part of your job as manager is to count the cash for the daily bank deposit. When you count the cash, you have 47 ones, 22 fives

cluponka [151]

Answer:

$592.92

Step-by-step explanation:

Bills:

47 ones = 47*1 = $47

22 fives = 22*5 = $110

9 tens = 9*10 = $90

17 twenties = 17*20 = $340

Total Bills: 47+110+90+340 = $587

Coins:

67 pennies = 67*1 = $0.67

12 nickels = 12*5 = $0.60

9 dimes = 9*10 = $0.90

15 quaters = 15*25 = $3.75

Total Coins: 0.67+0.6+0.9+3.75 = $5.92

Total: $587+$5.92 = $592.92

3 0

1 year ago

Victor wants to have at least 10 dozen cookies for the bake sale. Which of the following inequalities correctly represents the n

finlep [7]

Answer:

c ≥ 10 dozen

Step-by-step explanation:

Victor wants to have at least 10 dozen cookies for the bake sale.

In layman terms it can be understood as that Victor wants either 10 dozen cookies or more than that such as 11, 12, 13, 50 , 100 whatever number is greater than 10.

Let the no. of dozen of cookies wanted by him is c

according to condition

if victor wants either 10 dozen cookies

it can be represented mathematically as

c = 10 dozen (1)

_____________________________________

If victor wants no. of dozens of cookies greater than 10 .

it can be written as

c >10 dozen (2) (">" is symbol for greater than . expression simply means value of x should be greater than 10)

______________________________________________

now combining equation one and two, we have

c ≥ 10 dozen . It can means that x can take value starting from 10 to any no greater than..

7 0

2 years ago

Average box of crackers is 24.5 ounces with standard deviation of. 8 ounce. What percent of the boxes weigh more than 22.9 ounce

34kurt

Answer:

97.7% of of the boxes weigh more than 22.9 ounces.

15.9% of of the boxes weigh less than 23.7 ounces.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 24.5 ounces

Standard Deviation, σ = 0.8 ounce

We are given that the distribution of boxes weight is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(boxes weigh more than 22.9 ounces)

P(x > 22.9)

$P( x > 22.9) = P( z > \displaystyle\frac{22.9 - 24.5}{0.8}) = P(z > -2)$

$= 1 - P(z \leq -2)$

Calculation the value from standard normal z table, we have,

$P(x > 22.9) = 1 - 0.023 =0.977= 97.7\%$

97.7% of of the boxes weigh more than 22.9 ounces.

b) P(boxes weigh less than 23.7 ounces)

P(x < 23.7)

$P( x < 23.7) = P( z < \displaystyle\frac{23.7 - 24.5}{0.8}) = P(z < -1)$

Calculation the value from standard normal z table, we have,

$P(x < 23.7) =0.159= 15.9\%$

15.9% of of the boxes weigh less than 23.7 ounces.

7 0

2 years ago

Entering to par

alekssr [168]

Answer: you would simple multiply the cost c which is fifty bucks times the number of p people

Step-by-step explanation: how much would it cost for 6 people to go to the fair to solve this you would just set up the equation 6 * 50 and solve from there

6 0

2 years ago