Hi student, let me help you out! :)
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We are asked to find the two integers, given that they are consecutive, and their sum is 65.
- Consecutive integers are right next to each other, like 12 and 13. or 65 and 66.
Let the first integer be x, and let the second integer be x+1.
Their sum is 65. Let's set up our equation:
Combine like terms:
Subtract 1 from both sides of the equal sign:
Divide both sides by 2:
To find the second integer, subtract the first integer from the sum of the two integers:
The integers are: 33 and 32.
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Answer: What Item
Step-by-step explanation: And In What Quantity
Yes that’s it son welp ok
The correct answer is the first one(a): To get the system B,..., the first equation multiplied by 4...
Explanation:
1. Let us first multiple the first equation in System A with 4, we would get:
4(2x - y) = 4 * 3
=> 8x - 4y = 12 --- (A)
Now add the equation (A) and the second equation of System A:
8x - 4y = 12
3x + 4y = 10
------------------
11x = 22
Hence,
System B:
2x - y = 3
11x = 22
-i
The first question is c i believe, I dont have time to answer the others