Answer:
-7
Step-by-step explanation:
there is nothing to explain but anyways
-4 - 3 = -7
Y=2x^(1/2)
A=2⌠x^(1/2) dx
A=2[ (2/3)x^(3/2) ]
A=(4/3)[ x^(3/2) ] x=[1,4]
A=(4/3)(8-1)
A=(4/3)7
A=28/3 u^2
A=9 1/3 u^2
2x^2 + 25x + 50 not sure about the steps
Answer:
A) between 7:40 and 7:45
Step-by-step explanation:
Given,
The maximum time taken by her to walk to school = 15 minutes,
Since, the school starts on 8:00 AM,
Also, 15 minutes before 8:00 AM = 7:45 AM,
Thus, the maximum time at which she has to leave home = 7: 45 AM,
Hence, the reasonable estimate of the time she should leave home to get to school by 8:00 is between 7:40 and 7:45.
OPTION A would be correct.
