2 years ago

Find quadratic equation having zeroes as -3/alpha and 2/alpha

Mathematics

1 answer:

Degger [83]2 years ago

3 0

$(x-\frac{2}{\alpha})(x+\frac{3}{\alpha)}=x^{2}+\frac{x}{\alpha}-\frac{6}{\alpha^{2}}$

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