Answer:
0.0918
Step-by-step explanation:
We know that the average amount of money spent on entertainment is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.
The mean and standard deviation of average spending of sample size 25 are
μxbar=μ=95.25
σxbar=σ/√n=27.32/√25=27.32/5=5.464.
So, the average spending of a sample of 25 randomly-selected professors is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.
The z-score associated with average spending $102.5
Z=[Xbar-μxbar]/σxbar
Z=[102.5-95.25]/5.464
Z=7.25/5.464
Z=1.3269=1.33
We have to find P(Xbar>102.5).
P(Xbar>102.5)=P(Z>1.33)
P(Xbar>102.5)=P(0<Z<∞)-P(0<Z<1.33)
P(Xbar>102.5)=0.5-0.4082
P(Xbar>102.5)=0.0918.
Thus, the probability that the average spending of a sample of 25 randomly-selected professors will exceed $102.5 is 0.0918.
I don't seem to comprehend what you are asking?
Answer:
A. thats the answer
Step-by-step explanation:
carry on learning
B - Since it is a dotted inequality, it would be a equal to and something else. And since it is greater than 3, it would be X is equal to or less than 3
Answer:
x = 57°
Step-by-step explanation:
The angle not 76° or x° is 180-133 which is 47°. A triangles angles always sum up to 180° so:
76°+47°+x°=180°
123°+x°=180°
x°=57°