3,9,15 what is the 36th term

Mathematics

1 answer:

Yakvenalex [24]2 years ago

7 0

firstly, we have to find the difference

the diff is 6

we apply the concept diN+0

Di is difference

N is n

0 is first term - difference

first term is 3

diff is 6

3-6 = -3

nth term is 6n-3

then, we just substitute which is n is the 36th term

: 6(36)-3 = 213

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