2 years ago

Four equivalent forms of a quadratic function are given. Which form displays the zeros of function h?

Mathematics

1 answer:

Vedmedyk [2.9K]2 years ago

8 0

The Answer is : C.) h(x) = -4(x − 2)(x + 2)

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lora16 [44]

Answer:

2 2/5

Step-by-step explanation:

5/6 x-4 = -2

Add 4 to each side

5/6 x-4+4 = -2+4

5/6 x = 2

Multiply by 6/5 to isolate x

6/5 *5/6 x = 6/5 *2

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Changing this from an improper fraction

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Step-by-step explanation:

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$y=x^5(1-x)^6\\
y'=5x^4(1-x)^6+x^5\cdot6(1-x)^5\cdot(-1)\\
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y'=x^4(1-x)^5(5-5x-6x)\\
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Find the value of x. 16.2 0.03 38.5 34.8

ella [17]

Hi there!

$\large\boxed{x = 38.5}}$

To solve, we can use right triangle trig.

We are given the value of ∠A, and side "x" is its adjacent side. We are also given its opposite side, so:

tan (A) = O / A

tan (33) = 25 / x

Solve:

x · tan(33) = 25

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The answer is the letter B

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