Answer:
The average rate of change on the given interval is 9/70
Step-by-step explanation:
Here, we are to find the average rate of change of the function on the given interval
We proceed as follows;
on an interval [a,b] , we can find the average rate of change using the formula;
f(b) - f(a)/b-a
From the question;
a = 0
b = 3
f(0) = -3/5
f(3) = -3/14
Substituting the values, we have;
-3/14-(-3/5)/3-0
= 3/5-3/14/3
= (42-15)/70/3
= 27/70/3
= 27/70 * 1/3 = 9/70
Answer:
45
Step-by-step explanation:
if it has a subtraction or negative dash in front its negative.
i'm not sure how to solve the first one but the second is 150
Answer: x=−5 or x=5
Step-by-step explanation:
−3x4+27x2+1200=0
Step 1: Factor left side of equation.
−3(x2+16)(x+5)(x−5)=0
Step 2: Set factors equal to 0.
x2+16=0 or x+5=0 or x−5=0
x=−5 or x=5
First one:
you can add -10m and -13m but you can't add -10m and 2m^4 becuase the powers aren't the same so
when adding the like terms
look at the:
powers, (x^3 adds with x^3)
placehloder letter (x adds with x and y adds with y and so on)
-10m+2m^4-13m-20m^4
powers: m^1 and M^4
placeholders: all m
add
-10m-13m+2m^4-20m^4
-23m-18m^4
second one:
when multiplying exponents, you add with like
so if you multipliy
x^2yz^3 times x^4y^2z^2 thne you would get x^6y^3z^5
when multiply with coeficients
2x^2yz^3 times 4x^4y^2z^2=8x^6y^3z^5
so using associative property a(bc)=(ab)c
2/3 times p^4 times y^3 times y^4 times s^5 times 6 times p^2 times s^3
group like terms
(2/3 times 6) times (p^4 times p^2) times (y^3 times y^4) times (s^5 times s^3)
(4) times (p^6) times (y^7) times (s^8)
4p^6y^7s^8
