Answer:
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Step-by-step explanation:
Given - Azul spun a tri-color spinner twice.
To find - What is the probability that the spinner landed on the colors blue and green in any order?
Solution -
Given that,
A tri-color spinner spun twice
So,
The Sample Space, S = {BB, BG, BY, GB, GG, GY, YB, YG, YY}
⇒n(S) = 9
Now,
Let A be an event that the spinner landed on the colors blue and green
So,
A = {BG, GB}
⇒n(A) = 2
Now,
Probability that the spinner landed on the colors blue and green in any order = n(A) ÷ n(S)
= 2 ÷ 9
∴ we get
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Answer:
x>-4
Step-by-step explanation:
x-6>5x+10
x-5x>10+6
-4x<16
x<16/-4
x<-4
Answer:
-26= -9x + 10
-26 - 10= -9x
-36=-9x
-36:(-9)=x
4=x
Step-by-step explanation:
1. you pass +10 to the left in minus
2. you resolve what you've got on the left
then you pass the multiplying -9 to the left dividing
<h3>
Answer: 74</h3>
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Work Shown:
h(x) = 7x-5
h(2) = 7(2)-5
h(2) = 14-5
h(2) = 9
f(h(2)) = f(9)
f(x) = x^2-7
f(9) = 9^2-7
f(9) = 81-7
f(9) = 74
f(h(2)) = 74
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Here's a slightly alternative approach:
f(x) = x^2 - 7
f(h(x)) = ( h(x) )^2 - 7
f(h(x)) = ( 7x-5 )^2 - 7
f(h(2)) = ( 7*2-5 )^2 - 7
f(h(2)) = ( 14-5 )^2 - 7
f(h(2)) = ( 9 )^2 - 7
f(h(2)) = 81 - 7
f(h(2)) = 74
Answer:
7.5 m = 0.0075 km (Correct)
0.31 = 310 mm (Correct)
46 m = 4,600 cm (Correct)
457 mm =4.57 cm (Incorrect)
0.6 km = 6,000 m (Incorrect)
Step-by-step explanation:
Tell me if something is wrong.