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AleksAgata [21]

2 years ago

11

What system does it represent and what is the solution of this system

1 answer:

kicyunya [14]2 years ago

6 0

We can see that the lines intersect at (-5,3) on the graph, so that eliminates choices B and D. Both A and C say that the first line is y=x+8, which is true. A says that the second line is y+x=-2, and after isolating y, we get y=-x+2, which seems correct. Do the same for C, and you will find that it says the other equation is y=x-2, which is not true because it must have a negative slope. So your answer will be choice A.

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Which function has a range of y < 3?<br> y=3(2)*<br> y=2(3)<br> y=-(2)*+ 3<br> O y=(2]*_3

jasenka [17]

Answer:

The function given by $y = - (2)^{x} + 3$ will have a range of y < 3.

Step-by-step explanation:

The function given by $y = - (2)^{x} + 3$ will have a range of y < 3.

This is because, for any real values of x, the term $- (2)^{x}$ will have a negative value. If we put x = 1, then, $- (2)^{x}$ = - 2, and for x = -1, then $- (2)^{x}$ = - 0.5.

That means $- (2)^{x} < 0$ for all real x.

Hence, $- (2)^{x} + 3$ < 0 + 3

⇒ y < 3 for all real x. (Answer)

7 0

2 years ago

Answer this please.

seropon [69]

Answer:

3 ???

Step-by-step explanation:

7 0

2 years ago

Write the following number in scientific notation

Elodia [21]

Answer:

b

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Whats the sum of p 3/4

Gnoma [55]

The sum oh p 3/4 should be 3.333

6 0

2 years ago

Noel and Casey both start at the same place. Noel walks due south and Casey walks due east. After some time has passed, Noel is

Dovator [93]

Answer:

2.04 miles per hour

Step-by-step explanation:

Given

Noel

$n_1 =6miles$

$r_1 = 2mph$

Casey

$c_1 = 8miles$

$r_2 =1mph$

Required

The rate at which the distance increases

Their movement forms a right triangle and the distance between them is the hypotenuse.

At $n_1 =6miles$ and $c_1 = 8miles$

The distance between them is:

$d_1 = \sqrt{n_1^2 + c_1^2}$

$d_1 = \sqrt{6^2 + 8^2}$

$d_1 = \sqrt{100}$

$d_1 = 10miles$

After 1 hour, their new position is:

New = Old + Rate * Time

$n_2 = n_1 + r_1 * 1$

$n_2 = 6 + 2 * 1 = 8$

And:

$c_2 = c_1 + r_2 * 1$

$c_2 = 8 + 1 * 1 = 9$

So, the distance between them is now:

$d_2 = \sqrt{n_2^2 + c_2^2}$

$d_2 = \sqrt{8^2 + 9^2}$

$d_2 = \sqrt{145}$

$d_2 = 12.04$

The rate of change is:

$\triangle d = d_2 -d_1$

$\triangle d = 12.04 -10$

$\triangle d = 2.04$

5 0

2 years ago