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2 years ago

Preform the operation (answer in a+bi form) (i meaning imaginary number).

Mathematics

1 answer:

grin007 [14]2 years ago

7 0

$(3+\sqrt9)(2-\sqrt{-25})=\\
(3+3)(2-5i)=\\
6(2-5i)=\\
12-30i$

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Solve that for me :)

gavmur [86]

Answer:

2/5

Step-by-step explanation:

Out of the available options on the spinner, only 1 and 5 are factors of 25.

=> Outcomes = 2

=> Total outcomes = 5

P (factor of 25) = 2/5

Hope it helps.

5 0

1 year ago

Read 2 more answers

A jar has 15 red marbles,5 blue marbles,10 green marbles.what is the ratio of red marbles to the total number of marbles in simp

Misha Larkins [42]

Answer:

1:2

Step-by-step explanation:

The total number of marbles in the jar can be found by adding all the numbers of marbles given:

15+5+10 = 30

Out of 30 total marbles, 15 are red marbles. We can write the ratio as:

15:30

This ration can be simplified to:

1:2

7 0

2 years ago

Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega

AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

To find the simplified form of the given expression :

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

$=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2$ ( using the property $(ab)^m=a^m.b^m$ )

$=(2^6)(3^{-12})\times (2^{-6})(3^4)$ ( using the property $(a^m)^n=a^{mn}$

$=(2^6)(2^{-6})(3^{-12})(3^4)$ ( combining the like powers )

$=2^{6-6}3^{-12+4}$ ( using the property $a^m.a^n=a^{m+n}$ )

$=2^03^{-8}$

$=\frac{1}{3^8}$ ( using the property $a^{-m}=\frac{1}{a^m}$ )

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

6 0

2 years ago

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:( <br> A=?<br> B=?<br> please help me

Helen [10]

a= 16x+16

b= 40x + 15

Step-by-step explanation:

We know that perimeter of a rectangle is

$2(l + b)$

So therefore

$2(8x + 3 + 5) = a$

$= > 16x+ 6 + 10 = a$

$= > 16x + 16 = a$

Answer= A) that is perimeter is 16x+16

We know that area of a rectangle is l×b

So therefore

$(8x + 3) \times 5$

$= 40x + 15$

Answer = b) that is area is 40x + 15

7 0

1 year ago

MATH ALGEBRA QUESTION

Alexxx [7]

Easy
remember
x^-m=1/(x^m)

so

f(-1)=4*7^-1=4*(1/(7^1))=4*(1/7)=4/7
f(2)=4*7^2=4*49=196

5 0

2 years ago

Read 2 more answers