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2 years ago

Determine if the following equation is conditional equation, identity or a contradiction.

Mathematics

1 answer:

kow [346]2 years ago

3 0

Answer:

dont know

Step-by-step explanation:

dont know

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Is y=1/2x^2+5x-10 up or down

poizon [28]

Answer:

it is up

Step-by-step explanation:

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2 years ago

3x + 3y =15 and x = -3y -1

saul85 [17]

Answer:

(x, y) = (8, -3)

Step-by-step explanation:

You can substitute for x in the first equation:

3(-3y -1) +3y = 15

-6y = 18 . . . . . add 3 and simplify

y = -3 . . . . . . . divide by -6

x = -3(-3) -1 = 8 . . . . find x using the second equation

The solution to this system of equations is (x, y) = (8, -3).

4 0

2 years ago

Which polynomial functions are written in

PolarNik [594]

Answer:

c and d

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

PLEASE HELP WITH THIS AND ANSWER OT CORRECTLY WITH AN EXPLANATION PLEASE TYSM!

zaharov [31]

Answer:

I think the answer is 64 sqr foot try that and let me now

5 0

2 years ago

Verify identity: <br><br> (sec(x)-csc(x))/(sec(x)+csc(x))=(tan(x)-1)/(tan(x)+1)

Nikitich [7]

So hmmm let's do the left-hand-side first

$\bf \cfrac{sec(x)-csc(x)}{sec(x)+csc(x)}\implies \cfrac{\frac{1}{cos(x)}-\frac{1}{sin(x)}}{\frac{1}{cos(x)}+\frac{1}{sin(x)}}\implies 
\cfrac{\frac{sin(x)-cos(x)}{cos(x)sin(x)}}{\frac{sin(x)+cos(x)}{cos(x)sin(x)}}
\\\\\\
\cfrac{sin(x)-cos(x)}{cos(x)sin(x)}\cdot \cfrac{cos(x)sin(x)}{sin(x)+cos(x)}\implies \boxed{\cfrac{sin(x)-cos(x)}{sin(x)+cos(x)}}$

now, let's do the right-hand-side then

$\bf \cfrac{tan(x)-1}{tan(x)+1}\implies \cfrac{\frac{sin(x)}{cos(x)}-1}{\frac{sin(x)}{cos(x)}+1}\implies \cfrac{\frac{sin(x)-cos(x)}{cos(x)}}{\frac{sin(x)+cos(x)}{cos(x)}}
\\\\\\
\cfrac{sin(x)-cos(x)}{cos(x)}\cdot \cfrac{cos(x)}{sin(x)+cos(x)}\implies \boxed{\cfrac{sin(x)-cos(x)}{sin(x)+cos(x)}}$

7 0

2 years ago