All categories

2 years ago

Decimals from 12.4 to 13.8 with an interval of 0.2 between each pair of decimals

1 answer:

7 0

To solve this question, we begin with 12.4. The only operation you need to use for this problem is addition. We will slowly add 0.2 to 12.4 until we reach 13.8. As you add, be sure to align the decimal points! Also, remember to keep track of your numbers, as you will need them to answer the question.
12.4+0.2=12.6. 12.6+0.2=12.8. 12.8+0.2=13.0. 13.0+0.2=13.2. 13.2+0.2=13.4. 13.4+0.2=13.6. 13.6+0.2=13.8.
So, the decimals are (including 12.4 and 13.8): 12.4, 12.6, 12.8, 13.0, 13.2, 13.4, 13.6, and 13.8.
Hope this answered your question!

You might be interested in

13) -4= -b -1/3b and -23/3= 1/2a + 5/3a

Sergeeva-Olga [200]

-4=-1b-(1/3)b

-4=-(4/3)b

-4/-(4/3)=b

b=3

-------------------------------

(1/2)3+(5/3)2

3/6+10/6=13/6

-23/3=13/6a

(-23/3)/(13/6)=a

a=-46/13

7 0

2 years ago

Which statement about the ordered pairs (-9, 3) and (2, - 4) is true for the equation 6.0 6x - 142 2 9. 3) is a solution to the

CaHeK987 [17]

Answer:

It should be Neither ordered pair is a solution

Step-by-step explanation:

I take the same math lol

7 0

2 years ago

The circumference of a circle is 94.2 millimeters. What is the circle's radius?

notka56 [123]

Answer:

14.99

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Need help ASAP <br> questions in the pics i have sent

Cloud [144]

Answer:

Step-by-step explanation:

Picture 1

In right triangle ABC,

Side AB is the opposite side of angle C.

Picture 2

In triangle MKL,

tan(∠M) = $\frac{\text{Opposite side}}{\text{Adjacent side}}$

= $\frac{KL}{KM}$

= $\frac{15}{8}$

Option (1) is the answer.

Picture 3

In ΔXYZ,

sin(∠Z) = $\frac{\text{Opposite side}}{\text{Hypotenuse}}$

= $\frac{XY}{XZ}$

For the length of XY we will apply Pythagoras theorem in ΔXYZ,

XZ² = XY² + YZ²

XY² = XZ² - YZ²

= (40)² - (32)²

XY = √576

= 24

sin(Z) = $\frac{24}{40}$

sin(Z) = $\frac{3}{5}$

Picture 4

In right triangle DEF,

Cos(D) = $\frac{\text{Adjacent side}}{\text{Hypotenuse}}$

= $\frac{EF}{DF}$

= $\frac{75}{72}$

= $\frac{25}{24}$

Picture 5

In ΔABC,

tan(63°) = $\frac{\text{Opposite side}}{\text{Adjacent side}}$

tan(63°) = $\frac{BC}{AB}$

AB = $\frac{BC}{\text{tan}(63)}$

AB = $\frac{8}{\text{tan}(63)}$

AB = 4.0762 ≈ 4 m

Option (3) will be the answer.

7 0

2 years ago

The illuminance of a surface varies inversely with the square of its distance from the light source.If the illuminance of a surf

VashaNatasha [74]

Answer:

Distance between the surface and source of light will be increased by 6 meters.

Step-by-step explanation:

The illuminance of a surface varies inversely with the square of ts distance from the light source.

Let illuminance of the surface = x lumens per square meter

and distance from a light source = y meter.

Now x ∝ $\frac{1}{y^{2} }$

Or $x=\frac{k}{y^{2} }$ [k = proportionality constant]

Now we will find the value of k.

k = xy²

k = 120×(6)²

k = 4320

We have to calculate the distance of the source if illuminance of the surface is 30 lumens per square meter.

$30=\frac{4320}{y^{2}}$

y² = $\frac{4320}{30}$

y² = 144

y = √144 = 12 meters

So the source of the light will be shifted away from the surface = 12 - 6 = 6 meters.

6 0

2 years ago