Question

The rectangle below has an area of 30k^3 +6k^2 square meters. The width of the rectangle (in meters) is equal to the greatest common monomial factor of 30k^3 and 6k^2. What is the length and width of the rectangle?

Answer 1

Answer:

The width = 6k^2 m and the  length = 5k + 1 m.

Step-by-step explanation:

The GCF of 30k^3 and 6k^2 is 6k^2.

Width = 6k^2 (answer).

The length = area / width

=  (30k^3 + 6k^2)  / 6k^2

= 5k + 1  (answer).