The value of x that is the data point farthest from the line of best fit is 3
<h3>How to determine the x value farthest from the line of best fit?</h3>
The given parameters are:-
x Residual
3 -5
5 -1
7 3
9 0
Take the absolute value of the residuals
x Residual
3 5
5 1
7 3
9 0
The largest absolute value is 5
Hence, the value of x that is the data point farthest from the line of best fit is 3
Read more about residuals at:
brainly.com/question/16180255
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Answer:
Let x = number of units produced per hour before the line was modified , y = number of units produced per hour after the line was modified.
The null and alternative hypotheses are :
H0: μbefore = μafter
H1: μbefore ≠ μafter
Step 1: . Calculate the difference (D = y − x) between the two observations on each pair.
See attachment for (D=y-x)
step 2: Calculate ∑D and ∑D2
From table we get ∑D = -10 & ∑D2 = 72
Step 3: Put all the value in test statistic "t"
t = D/√nD^2-D^2/n - 1
t =-10/√6.72-(-10)^2/6-1
t= -10√66.4
= -10/8.1486
= -1.227
Step 4: Compare tcal and ttab
At α = 0.05
t0.05 for 5 d.f. = 3.1634 (two tail test)
Hence | tcal | < t0.05
So, we accept the hypothesis.
So we conclude that the modified (after) layout has not increased worker productivity at 5% level of significance.
Answer:
The slope is 3/2
Step-by-step explanation:
I put both coordinates into MathPapa and it told me that that's the slope
Given :
Set of x-intercepts {-3,1,7},
point through which it passes (-2,54)
Now,
Step 1: Substitute value of x intercepts in equation, 
, we get,
... equation (1)
Step 2: substitute x an y with the point through which it passes,
∴ 
Step 3: Now, substituting value of a in equation (1), we have
(Requited cubic equation)
