The 3 numbers which should be placed between 12 and 60 are; 24, 36 and 48.
<h3>What three numbers should be placed between 12 and 60?</h3>
It follows from the task content that the first and last numbers are; 12 and 60 respectively.
Hence, since the difference between 12 and 60 is 48 and there are 4 transitions between the two numbers to have 5 total numbers,
It follows that the common difference is; 48/4 = 12 and the three numbers required are; 24,36 and 48.
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Multiples of 8 through 60 are 8, 16, 24, 32, 40, 48 and 56
No. of favorable outcomes= 7
Thus, P(E)=7/60
I believe it is B, because going down would be negative, and it is subtracting 6.
Answer:
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