According to the Fundamental Theorem of Algebra, the number of zeros or roots of the equation is equal to the highest degree among the terms. So with the given real roots 4, and -8 <span>the order should be 2 or a binomial. We expound (x-4) * (x+8) to give </span><span> x2 + 4x - 32 = 0</span>
The equation of a line that passes through (x1,y1) and has a slope of m is
y-y1=m(x-x1)
find slope
slope between (x1,y1) and (x2,y2) is
(y2-y1)/(x2-x1)
given
(-3,2) and (2,1)
slope=(1-2)/(2-(-3))=(-1)/(2+5)=-1/5
pikc a point
if we pick (-3,2)
(x1,y1)
x1=-3
y1=2
y-2=-1/5(x-(-3))
y-2=-1/5(x+3)
that is D
Here s the question this is the doc i put it on please help
1)
x^2 + (3y/2z) = 7
2x^2z + 3y = 14z
3y = 14z - 2x^2z
3y = 2z(7 - x^2)
y = 2/3(z)(7 - x^2)
2)
(3zx^4) /(5+z) = 2y
3zx^4 = 2y(5+z)
3zx^4 = 10y + 2yz
Step-by-step explanation:
CCC and I have a very different view on the situation than the one I have been using for me since 6AM when you have been in the same situation for me and my
