A. The figure is a triangular pyramid. You can findits surface area by adding up the area of the three faces of the triangle and the area of the base. A derived formula also is used where the SA is equal to 12 times the perimeter of base times the slant height, added to that is the area of the base. The area of the square base is s^2. Its perimeter is 4s.
SA of Pyramid = 12*P*l + s^2
SA of Pyramid = 12*4s*l + 16^2
SA of Pyramid = 12*4(16)*(17) + (16)^2
SA of Pyramid = 11,008 square inches
b.) The formula for the SA of a cone is:
SA of cone = πr[r+√(h^2+r^2)]
SA of cone = π(3)[(3+√(8^2+3^2)]
SA of cone = 108.8 square inches
I hope I’m not too late. Substitute x = 4y + 5y = 2
y = 2. Substitute this value into the first equation: x + -4 x 2 = -8. So the answer is (-8,2).
Answer:
Down below
Step-by-step explanation:
a. The range of y = sinθ is [-1,1]
b. The period of y = cosθ is 2π
c. The asymptotes of y = tanθ are -π2, π2, πn
d. The amplitude of y = sinθ is 1
e. The period of y = tanθ is π
f. The max value of y = cosθ is 1
36
Step-by-step explanation:
4 5/8*3 is 13.875
500 decided by 13.875 is a little over 36, so you can make 36 full ribbons
