Start weight- 8.03
week 1 - 8.8
week 2 - 8.13
week 3 - 9.03
week 4 - 9.08
So, the Omar should weigh 9 pounds 8 ounces by the end of 4 weeks.
I hope this helped!
Answer:
Required equation is: 25n = 875
Step-by-step explanation:
Let n be the number of minutes Jonathon read per day
Now
He read for 25 days and total 875 minutes
The equation will be:
We can solve this equation to find the number of minutes each day
Using Division property of Equality
Hence,
Required equation is: 25n = 875
The trigonometric ratios show that the angle FHE is 48.59°.
<h3>RIGHT TRIANGLE</h3>
A triangle is classified as a right triangle when it presents one of your angles equal to 90º. The greatest side of a right triangle is called hypotenuse. And, the other two sides are called cathetus or legs.
The math tools applied for finding angles or sides in a right triangle are the trigonometric ratios or the Pythagorean Theorem.
The Pythagorean Theorem says: . And the main trigonometric ratios are:
It is important to remember that the sum of internal angles for any triangle is 180°.
From the question, it is possible to see 2 right triangles (HGF and FHE).
You can find the hypotenuse of the triangle HGF from the trigonometric ratio: sen Θ
The hypotenuse of triangle HGF is one of legs for the triangle FHE. The, you can find the angle FHE from the trigonometric ratio: tan β. Thus,
Learn more about trigonometric ratios here:
brainly.com/question/11967894
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Answer and Explanation:
A function is said to be increasing, if the derivative of function is f’(x) > 0 on each point. A function is said to be decreasing if f”(x) < 0.
Let y = v (z) be differentiable on the interval (a, b). If two points z1 and z2 belongs to the interval (a, b) such that z1 < z2, then v (z1) ≤ v (z2), the function is increasing in this interval.
Similarly, the function y = v(z) is said to be decreasing, when it is differentiable on the interval (a , b).
Two points z1 and z2 Є (a, b) such that z1 > z2, then v (z1) ≥ v(z2). The function is decreasing on this interval.
The function y = v (z)
The derivative of function Y’ = v’(z) is positive, then the function is increasing.
The function y = v (z)
The derivative of function y’ is negative, then the function is decreasing.