The balanced equation is
Cl₂ + SO₂ +2H₂O ⟶ 2Cl⁻ +SO₄²⁻ + 4H⁺
This is a <em>redox reaction</em>, so I will balance it using the <em>ion-electron method</em>.
<em>Step </em>1. Write the <em>skeleton equatio</em>n.
Strip the equation of H⁺ and H₂O (these come back in during the balancing procedure). We get
Cl₂ + SO₂ ⟶ Cl⁻ +SO₄²⁻
<em>Step 2</em>: Separate the skeleton equation into <em>two half-reactions</em>.
Cl₂ ⟶ Cl⁻
SO₂ ⟶ SO₄²⁻
<em>Step 3</em>: Balance all atoms <em>other than H and O</em>.
Cl₂ ⟶ 2Cl⁻
SO₂ ⟶ SO₄²⁻
<em>Step 4</em>: <em>Balance O</em>.
Add enough H₂O molecules to balance O,
Cl₂ ⟶ 2Cl⁻
SO₂ + 2H₂O ⟶ SO₄²⁻
<em>Step 5</em>: <em>Balance H</em>.
Add enough H⁺ ions to balance H.
Cl₂ ⟶ 2Cl⁻
SO₂ + 2H₂O ⟶ SO₄²⁻ + 4H⁺
<em>Step 6</em>:<em> Balance charge.
</em>
<em>Add</em> <em>electrons</em> to the side that needs more negative charge.
Cl₂ + 2e⁻ ⟶ 2Cl⁻
SO₂ + 2H₂O ⟶ SO₄²⁻ + 4H⁺ + 2e⁻
<em>Step </em>7: <em>Add the two half-reactions</em>.
The balanced equation is
Cl₂ + SO₂ + 2H₂O ⟶ 2Cl⁻ + SO₄²⁻ + 4H⁺