A line passes through the two points (-4,6) and (2,-5). 11x +6y - 80 = 0 is the given line equation.
<h3>What is the slope of a line which passes through points ( p,q) and (x,y)?</h3>
Its slope would be:
The slope of parallel lines are same. Slopes of perpendicular lines are negative reciprocal of each other.
The slope m of the line is given as
The equation of a line is
Hence, the equation is 11x +6y - 80 = 0
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Answer:
D
Step-by-step explanation:
The equation of a circle centred at the origin is
x² + y² = r² ( where r is the radius )
Here r = 15, thus
x² + y² = 15² , that is
x² + y² = 225 → D
Answer:
X-8 is the best answer there