A helium-filled balloon escapes a child's hand at sea level and 21.1 deg C. When it reaches an altitude of 3000 m, where the tem
perature is 4.8 deg C and the pressure is only 0.72 atm , how will its volume compare to that at sea level?
1 answer:
Answer:
Explanation:
Well use the combines gas law to evaluate this question;
P₁V₁/T₁ = P₂V₂/T₂ (Remember that at sea level the pressure is usually 1 atm)
1 * V₁ / 294.25 = 0.72 * V₂ / 277.95 (NB: Temperatures have to be in Kelvin)
V₁ / 294.25 * 277.95 = 0.72 V₂
0.945 V₁ = 0.72 V₂
0.945/0.72 V₁ = V₂
1.312 V₁ = V₂
The volume (V2) at 3000 m altitude will be <u>1.312 </u>bigger than the initial volume at sea level.
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