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2 years ago

9

Thx and have a great day!!

1 answer:

In-s [12.5K]2 years ago

3 0

Answer:

Therefore,

IU = 7x = 7×1 = 7 units

Step-by-step explanation:

Given:

Δ TRU and Δ IRU are right angle triangle.

TU = 2x + 5

IU = 7x

RU = common Hypotenuse

To Find:

IU = ?

Solution:

In right angle triangles Δ TRU and Δ IRU we have sine identity as

$\sin (\angle TRU)= \frac{\textrm{side opposite to angle TRU}}{Hypotenuse} \\\\\\and\\\sin (\angle IRU)= \frac{\textrm{side opposite to angle IRU}}{Hypotenuse}$

Now,

∠ TRU = ∠ IRU = 19° ............Given

Substituting the given values in it we get

$\sin 19=\frac{2x+5}{RU} \\and\\\sin 19=\frac{7x}{RU} \\\textrm{on equating both the equation we get}\\\\7x=2x+5\\7x-2x=5\\\\5x=5\\\\x=\frac{5}{5} \\\\x=1$

Therefore,

IU = 7x = 7×1 = 7 units

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Convert the following degree measure to radian measure. 150 degrees

slamgirl [31]

Answer:

2.617

Step-by-step explanation:

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2 years ago

You enter a relay race. To start, you must run 20 yards to Checkpoint A. You then must turn and run 12 yards to Checkpoint B. La

Anarel [89]

Distance to checkpoint A from starting line = 20 yards.

Then from A to B distance = 12 yards.

Let us take starting point C.

So, it would make a right triangle.

We have AB = 12, AC = 20, we need to find BC, that is Hypotenuse of the right triangle.

According to Pythagoras theorem:

$BC^2 = AB^2+AC^2$

$BC^2 = 12^2+20^2$

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2 years ago

Read 2 more answers

nikitadnepr [17]

The answer is
x=2t and t=x/2, but we have <span>y = 3t -1
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so y = 3x/2 - 1</span>

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2 years ago

What is the following product?

KiRa [710]

ANSWER

$2 \sqrt{42} +7 \sqrt{2}- 6- \sqrt{21}$

EXPLANATION

The given product is:

$( \sqrt{14} - \sqrt{3} )( \sqrt{12} + \sqrt{7} )$

We expand using the distributive property to obtain:

$\sqrt{14}( \sqrt{12} + \sqrt{7}) -\sqrt{3}( \sqrt{12} + \sqrt{7} )$

Extract the perfect squares to get:

$\sqrt{14}(2 \sqrt{3} + \sqrt{7}) -\sqrt{3}( 2\sqrt{3} + \sqrt{7} )$

Expand further to get;

$2 \sqrt{42} +7 \sqrt{2}- 2(3) - \sqrt{21}$

This simplifies to,

$2 \sqrt{42} +7 \sqrt{2}- 6- \sqrt{21}$

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2 years ago

2 r squared + 3s cubed minus r squared + 40 squared minus r squared if R equals -2 s equals -3 and T equals 5

Flura [38]

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2 years ago