All categories

2 years ago

What is the area of the given circle in Terms of Pi?

Mathematics

2 answers:

devlian [24]2 years ago

7 0

Numbers i think

or decimals

weeeeeb [17]2 years ago

3 0

I think it would be 27.38ᴹ2

You might be interested in

What is the solution of StartRoot 2 x 4 EndRoot = 16?.

Ludmilka [50]

Answer:

start with root and minus with 2 and 5 and answer 16b

8 0

2 years ago

A soccer ball is kicked from 3 feet above the ground. the height,h, in feet of the ball after t seconds is given by the function

dexar [7]

Here's our equation.

$h=-16t+64t+3$

We want to find out when it returns to ground level (h = 0)

To find this out, we can plug in 0 and solve for t.

$0 = -16t+64t+3 \\ 16t-64t-3=0 \\ use\ the\ quadratic\ formula\ \frac{-b\±\sqrt{b^2-4ac}}{2a} \\ \frac{-(-64)\±\sqrt{(-64)^2-4(16)(-3)}}{2*16} = \frac{64\±\sqrt{4096+192}}{32}$

$= \frac{64\±\sqrt{4288}}{32} = \frac{64\±8\sqrt{67}}{32} = \frac{8\±\sqrt{67}}{4} = \boxed{\frac{8+\sqrt{67}}{4}\ or\ 2-\frac{\sqrt{67}}{4}}$

So the ball will return to the ground at the positive value of $\boxed{\frac{8+\sqrt{67}}{4}}$ seconds.

What about the vertex? Simple! Since all parabolas are symmetrical, we can just take the average between our two answers from above to find t at the vertex and then plug it in to find h!

$\frac{1}2(\frac{8+\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(2+\frac{\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(4) = 2$

$h=-16t^2+64t+3 \\ h=-16(2)^2+64(2)+3 \\ \boxed{h=67}$

8 0

3 years ago

(y - 2)2 = y2 – 6y + 4<br> Is this statement true or false?

trasher [3.6K]

<h3>Answer: False</h3>

==============================================

Explanation:

I'm assuming you meant to type out

(y-2)^2 = y^2-6y+4

This equation is not true for all real numbers because the left hand side expands out like so

(y-2)^2

(y-2)(y-2)

x(y-2) .... let x = y-2

xy-2x

y(x)-2(x)

y(y-2)-2(y-2) ... replace x with y-2

y^2-2y-2y+4

y^2-4y+4

So if the claim was (y-2)^2 = y^2-4y+4, then the claim would be true. However, the right hand side we're given doesn't match up with y^2-4y+4

--------------------------

Another approach is to pick some y value such as y = 2 to find that

(y-2)^2 = y^2-6y+4

(2-2)^2 = 2^2 - 6(2) + 4 .... plug in y = 2

0^2 = 2^2 - 6(2) + 4

0 = 4 - 6(2) + 4

0 = 4 - 12 + 4

0 = -4

We get a false statement. This is one counterexample showing the given equation is not true for all values of y.

6 0

2 years ago

Read 2 more answers

jen makes a rectangular banner. it is 3/4 yard long and 1/4 yard wide. what is the area, in square yards of the banner

SashulF [63]

Ok so in order to find the answer to this problem we are going to Multiply $\frac{3}{4}$ and $\frac{1}{4}$ . $\frac{3}{4}* \frac{1}{4}= \frac{3}{4}
$ $Answer:\boxed{ \frac{3}{4}} \\ 
$

8 0

2 years ago

Read 2 more answers

In a survey respondents were asked which type of movie they watched most often. the bar graph shows how many males and how many

Y_Kistochka [10]

Males that watched action movies : 13
males that watched drama movies : 5

so there are (13 - 5) = 8 more that watched action then drama

6 0

2 years ago

Read 2 more answers