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3 years ago

10(8+3h) need help asap

Mathematics

2 answers:

LuckyWell [14K]3 years ago

3 0

Answer:

80 + 30h

Step-by-step explanation:

10(8+3h)

Distribute

10*8 + 10*3h

80 + 30h

ANTONII [103]3 years ago

3 0

80 + 30h

Steps:

10(8+3h) - you have to distribute the 10 into the parentheses

80 + 30h

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Pls help ill give a 100 jusrt answer these question and ill even give brainliest

mojhsa [17]

Answer:

That is a lot of questions to answer. But I will try.

a) 6 square units

b) 5/6

Second picture

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2. Area = 4.5

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5. Area = 17.5

Third picture

a) 8 units because if you move the bottom triangle to the top of the other triangle it makes a rectangle with height of 2 and length of 4.

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2 years ago

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Write the fact family for these factors: 8, 64

natka813 [3]

Answer:

8*64=512

64*8=512

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2 years ago

Solve the initial value problem: y'(x)=(4y(x)+25)^(1/2) ,y(1)=6. you can't really tell, but the '1/2' is the exponent

goblinko [34]

Answer:

$y(x)=x^2+5x$

Step-by-step explanation:

Given: $y'=\sqrt{4y+25}$

Initial value: y(1)=6

Let $y'=\dfrac{dy}{dx}$

$\dfrac{dy}{dx}=\sqrt{4y+25}$

Variable separable

$\dfrac{dy}{\sqrt{4y+25}}=dx$

Integrate both sides

$\int \dfrac{dy}{\sqrt{4y+25}}=\int dx$

$\sqrt{4y+25}=2x+C$

Initial condition, y(1)=6

$\sqrt{4\cdot 6+25}=2\cdot 1+C$

$C=5$

Put C into equation

Solution:

$\sqrt{4y+25}=2x+5$

$4y+25=(2x+5)^2$

$y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$

$y(x)=x^2+5x$

Hence, The solution is $y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$ or $y(x)=x^2+5x$

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2 years ago

Sergio passes by a bike store on Monday and sees his dream bike in the window. It cost 120 . He passes by on Wednesday and is th

insens350 [35]

Answer:

Step-by-step explanation:

120 - (120/4)

120 - 30 = 90

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2 years ago

(-5,7) and (2,5) <br> find the slope of the line passing through the given points

svp [43]

Answer: -2/7

Step-by-step explanation:

To find the slope, you use the formula $m=\frac{y_2-y_1}{x_2-x_1}$ .

$m=\frac{5-7}{2-(-5)} =\frac{-2}{7}=-\frac{2}{7}$

Now, we know the slope is -2/7.

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2 years ago