What are you trying to ask? Are you saying a family eats 1 bread 2 bread 3 bread each meal which combination will allow for 2 meals?
If so it’s 1 and 2 if your saying they eating 1 2 3 bread each meal 3 isn’t enough
Answer:
b) 0.42
Step-by-step explanation:
Let A be the event that card is a heart card and B be the event that card is a face card.
We have to find P(A or B). P(A∪B)=?
P(A∪B)=P(A)+P(B)-P(A∩B)
There are 13 heart cards and 12 cards are face cards. There would be 3 face card in hearts. So,
P(A)=13/52=1/4=0.25
P(B)=12/52=3/13=0.231
P(A∩B)=3/52=0.058
P(A∪B)=0.25+0.231-0.058
P(A∪B)=0.481-0.058
P(A∪B)=0.423
So, the probability that the card is a heart or is a face card is about is 0.42.
Answer:
That its a problem there u go
Step-by-step explanation:
Well you subtract d from both sides with would make 2D-4=-8. Then you subtract four to both sides which is -12. Then you divide -12 by 2D which is 6. D=-6
"<span>How much did your classmates typically spend on music downloads last year?" is a statistical question, and the units would </span>be both the number of students and how many downloads each individual bought.