I think your answer would be a line or a ray
I hope this helps!
2/5 = x/10
2/5 x 2 = 4/10
x= 4
2/5 = 4/10
12 adult elephants, 6 young elephants = 18 total :)
(2y+3)(3y^2+4y+5)
so u just multiply all the things from different brackets.
2y*3y^2 = 6y^3
2y*4y = 8y^2
2y*2 = 4y
3*3y^2 = 9y^2
3*4y = 12y
3*5 = 15
so 6y^3+8y^2+4y+9y^2+12y+15
thats the answer BUT u need to collect the like terms, otherwise u probably wont get full marks on the question, so:
6y^3+17y^2+16y+15
i hope this helps :)
someone correct me if im wrong
For this case what we must do is define h (x), which is given by:
h (x) = f (x) * g (x)
Where,
f (x) = 5 (The number of fish breeding farms)
g (x) = 80 (1.04) ^ x (The approximate number of fish per breeding farm)
Substituting we have:
h (x) = (5) * (80 (1.04) ^ x)
Rewriting we have:
h (x) = 400 (1.04) ^ x
Answer:
the approximate population of the fish across all Mr. Dawson's farms after x months is:
h (x) = 400 (1.04) ^ x