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2 years ago

Subject Algebra 1

Mathematics

1 answer:

Mashutka [201]2 years ago

6 0

Answer:

$10x^{2}-34$

Step-by-step explanation:

Because we are told equivalent expressions for y and z we can plug those in to 2(y+z).

$2((3x^{2}+x^{2}-5)+(x^{2}-12))$

Then simplify by combining like terms of the expressions. Values ending in x^2 can be combined with each other.

$2(5x^{2}-17)$

Now we can distribute the 2 by multiplying each value in the parentheses by 2.

$10x^{2}-34$

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Heyyy.... can someone pls help asap. Rearrange the formula to write r in terms of P and pi.

bearhunter [10]

Step-by-step explanation:

p = 2r + pi×r

p = r(2 + pi)

r = p/(2 + pi)

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1 year ago

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Help please. Thanks :3

VashaNatasha [74]

(a.) constant of proportionality k
y = kx
y/x = k
use the point (1,30)
30 = k

The slope will be the same answer, theyre the same thing
use two points (1,30) and (2,60)
m = (60-30)/(2-1) = 30

(b.) The equation for the line is: y = 30x

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2 years ago

For the upcoming holiday season, Dorothy wants to mold 20 bars of chocolate into tiny pyramids. Each bar of chocolate contains 6

gizmo_the_mogwai [7]

So each bar contains 6 and she has 20 so 6 times 20=120

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v=base times height times 1/2
v=1 times 2 times 1/3
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she can make 180 pyramids

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2 years ago

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I have a shuffled deck of 52 playing cards. A deck of cards has four different suits, with an even number of cards in each. I pi

zzz [600]

Answer:

The probability is 0.25

Step-by-step explanation:

Here is a probability question.

We want to know the probability of picking a card which is in the spades suit.

Now, what we know is that there are a total of 52 cards and we have 4 suites.

Each suite have equal number of cards. So definitely the number of cards in the spades suit will be 52/4 = 13 cards

Thus, the probability of picking any card in the spades suit = number of cards in the spades suit/ Total number of cards in the deck

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2 years ago

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masya89 [10]

Answer:

The image will be congruent to ΔMNP.

Line EG will be perpendicular to the line segments connecting the corresponding vertices.

The line segments connecting corresponding vertices will all be parallel to each other.

Step-by-step explanation:

The reflected image will be the mirror image of ΔMNP, so it will be congruent. The lines connecting each vertex to the corresponding vertex will be parallel, and all three lines are perpendicular to EG.

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2 years ago