Domain is [-10,∞)
2 is included , only at x=2 new function begins
Range is the values of y , so range is [-7]∪[-4,6
I think, it should be like this.
Subtract 33 from both sides
6x>3x+30-36x>3x+30−3
Simplify 3x+30-33x+30−3 to 3x+273x+27
6x>3x+276x>3x+27
Subtract 3x3x from both sides
6x-3x>276x−3x>27
Simplify 6x-3x6x−3x to 3x3x
3x>273x>27
Divide both sides by 3
3x>\frac{27}{3}x>
3x> 27
Simplify \frac{27}{3}
3
ANSWER: x>9
Answer:
d) 5/3 x
Step-by-step explanation:
You substitute a for 2c and b for 5d, so your equation will look like this:
c/d - 2c/5d = x
Then you just simplify into x by making c/d into 5c/5d so you have a common denominator.
5c/5d - 2c/5d = x
3c/5d = x
5/3 is your answer
Complex numbers have the form a + ib. Given a + ib, the complex conjugatet is a - ib.
Therefore, the complex conjugate of -1 + 3i is -1 - 3i.
