9514 1404 393
Answer:
DE = 86
EF = 84
Step-by-step explanation:
We assume that point E lies on segment DF, so that ...
DE + EF = DF
(3x +20) +(2x +40) = 170
5x = 110 . . . . . . . . . . . . . . . collect terms, subtract 60
x = 22 . . . . . . . . . . . . divide by 5
DE = 3×22 +20 = 66 +20 = 86
EF = 2×22 +40 = 44 +40 = 84
Answer:
2nd option will be the answer (y=4x²+48x+146)
Step-by-step explanation:
y=4(x+6)²+2
y=4(x²+2*x*6+6²)+2 [(a+b)²=a²+2ab+b²]
y=4(x²+12x+36)+2
y=4(x²)+4(12x)+4(36)+2
y=4x²+48x+144+2
y=4x²+48x+146
14
You are taking away 6 each time
Answer: 37477/100000
Step-by-step explanation:
The original air present after 8 breaths will be equal to 179.81 ml.
<h3>What is an equation?</h3>
The equation in mathematics is the relationship between the variables and the number and establishes the relationship between the two or more variables.
It is given in the question that:-
During normal breathing, about 12% of the air in the lungs is replaced after one breath
If the initial amount of air in the lungs is 500 mL
how much of the original air is present after 8 breaths?
The calculation for the eduction of the air will be done by the following equation:-
=179.88 ml
Hence original air present after 8 breaths will be equal to 179.81 ml.
To know more about equations follow
brainly.com/question/2972832
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