Answer:
-6i
Step-by-step explanation:
Complex roots always come in pairs, and those pairs are made up of a positive and a negative version. If 6i is a root, then its negative value, -6i, is also a root.
If you want to know the reasoning, it's along these lines: to even get a complex/imaginary root, we take the square root of a negative value. When you take the square root of any value, your answer is always "plus or minus" whatever the value is. The same thing holds for complex roots. In this case, the polynomial function likely factored to f(x) = (x+8)(x-1)(x^2+36). To solve that equation, you set every factor equal to zero and solve for the x's.
x + 8 = 0
x = -8
x - 1 = 0
x = 1
x^2 + 36 = 0
x^2 = -36 ... take the square root of both sides to get x alone
x = √-36 ... square root of an imaginary number produces the usual square root and an "i"
x = ±6i
Answer:
2x + y = 3.75
3x + 2y = 6
Step-by-step explanation:
x = cost of 1 hot dog
y = cost of 1 drink
Neveah: 2x + y = 3.75
Jason: 3x + 2y = 6
200 miles
$71-$35=$36 left in budget
$36/.18 per mile= 200 miles
9514 1404 393
Answer:
34
Step-by-step explanation:
Maybe you want to evaluate ...
16 - 14 ÷ 2 + (3 +2)²
The parentheses are evaluated first.
16 -14÷2 +5²
Then the exponential term.
16 -14÷2 +25
The division is evaluated next.
16 -7 +25
Finally, the sum is evaluated.
= 9 +25
= 34
____
Your calculator can do this arithmetic for you.
hello :<span>
<span>an equation of the circle Center at the
A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a = -7 and b = -1 (Center at: A(-7,-1) )
r = AP.... P(8,7)
r² = (AP)²
r² = (8+7)² +(7+1)² =225+64=289 ...... so : r = 17
an equation of the circle that satisfies the stated conditions.
Center at </span></span>A(-7,-1), passing through P(8, 7) is :
(x+7)² +(y+1)² = 289
The point (-15,y ) <span>lies on this circle : (-15+7)² +(y+1)² = 289....(subsct : x= -15)
(y+1)² = 225
(y+1)² = 15²
y+1 = 15 or y+1 = -15
y = 14 or y = -16
you have two points : (-15,14) , (-15, -16)</span>
