For a binomial experiment in which success is defined to be a particular quality or attribute that interests us, with n=36 and p as 0.23, we can approximate p hat by a normal distribution.
Since n=36 , p=0.23 , thus q= 1-p = 1-0.23=0.77
therefore,
n*p= 36*0.23 =8.28>5
n*q = 36*0.77=27.22>5
and therefore, p hat can be approximated by a normal random variable, because n*p>5 and n*q>5.
The question is incomplete, a possible complete question is:
Suppose we have a binomial experiment in which success is defined to be a particular quality or attribute that interests us.
Suppose n = 36 and p = 0.23. Can we approximate p hat by a normal distribution? Why? (Use 2 decimal places.)
n*p = ?
n*q = ?
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Answer:
I think its 71
Step-by-step explanation:
Well the average between -3 -2 and -1 seems to be -2, so all i do is 95-24 and you get 71, either that or 65. I highly think its 71 though
3x = B
(x + 80 = 1/2B) * -3
-3x-240 = -3/2B
-240 = -1/2B
B=480 pennies
Answer:
See below.
Step-by-step explanation:
I see there are no answer choices you've provided, but in order to interpret a confidence interval correctly, you might say something like "We are 90% confident that the true difference in the mean number of drops is contained within the interval".
