A negative charged particle of known magnitude q is placed in a uniform electric field of known strength E. What additional info
1 answer:
Answer:d
Explanation:
Electric field is a region around charged particle where charged particle experience a force .
Magnitude of Force experienced by charged particle is given by
where F=force experienced by charged particle
q=charge of particle
E=strength of electric field
If q and E are given then no additional information is needed to determine the magnitude of force.
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Answer:
a)
b)
Explanation:
Searching the missed information we have:
E: is the energy emitted in the plutonium decay = 8.40x10⁻¹³ J
m(⁴He): is the mass of the helium nucleus = 6.68x10⁻²⁷ kg
m(²³⁵U): is the mass of the helium U-235 nucleus = 3.92x10⁻²⁵ kg
a) We can find the velocities of the two nuclei by conservation of linear momentum and kinetic energy:
Linear momentum:
Since the plutonium nucleus is originally at rest, :
(1)
Kinetic Energy:
(2)
By entering equation (1) into (2) we have:
Solving the above equation for we have:
And by entering that value into equation (1):
The minus sign means that the helium-4 nucleus is moving in the opposite direction to the uranium-235 nucleus.
b) Now, the kinetic energy of each nucleus is:
For He-4:
For U-235:
I hope it helps you!