Answer:
C. 6
Step-by-step explanation:
So it says read less thann 25 books --> that means the numbers are 13,14,14,16,19,21,21,22,23, and 24 --> a total of 10 numbers
Then it says read more than 35 books --> that means the numbers are 37,41,42,43 --> a total of 4 numbers
Now, it says how many more --> that means you subtract 4 by 10 = 10 - 4 = 6
Therefore the answer is 6 more students read less than 25 books than read more than 35 books.
Answer:
12^5
Step-by-step explanation:
36^5=3^5×x^5
36÷3=12
Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.
Step-by-step explanation:
Since we have given that
Integers between 10000 and 99999 = 99999-10000+1=90000
n( divisible by 3) = 
n( divisible by 5) = 
n( divisible by 7) = 
n( divisible by 3 and 5) = n(3∩5)=
n( divisible by 5 and 7) = n(5∩7) = 
n( divisible by 3 and 7) = n(3∩7) = 
n( divisible by 3,5 and 7) = n(3∩5∩7) = 
As we know the formula,
n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)
Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.
Answer:
x=30, <A=60, <C=30
Step-by-step explanation:
A triangle always has its total angles added up to 180 degrees, so we can set up the following equation:
90+2x+x=180
90+3x=180
3x=90
x=30
Since x=30, this means <C is 30 degrees. For <A, it's twice as much as <C, so 2*30=60.
So x=30, <A=60, <C=30
Hope this helped!
Answer:
Height of the fighter plane =1.5km=1500 m
Speed of the fighter plane, v=720km/h=200 m/s
Let be the angle with the vertical so that the shell hits the plane. The situation is shown in the given figure.
Muzzle velocity of the gun, u=600 m/s
Time taken by the shell to hit the plane =t
Horizontal distance travelled by the shell =u
x
t
Distance travelled by the plane =vt
The shell hits the plane. Hence, these two distances must be equal.
u
x
t=vt
u Sin θ=v
Sin θ=v/u
=200/600=1/3=0.33
θ=Sin
−1
(0.33)=19.50
In order to avoid being hit by the shell, the pilot must fly the plane at an altitude (H) higher than the maximum height achieved by the shell for any angle of launch.
H
max
=u
2
sin
2
(90−θ)/2g=600
2
/(2×10)=16km
