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2 years ago

Celina and Richard spend a certain amount of money from their money box each month to buy plants.

Mathematics

1 answer:

loris [4]2 years ago

5 0

Answer:

100

Step-by-step explanation:

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A triangle has one side that measures 4x and two sides that measure x + 5 each. Write an

Tamiku [17]

P = 4x + 2(x + 5)
That’s the expression
P = perimeter

5 0

2 years ago

Do you know the answer? HELP?

Georgia [21]

V=LWH
if legnth AND width AND height are dobuled
V=2L2W2H
V=2*2*2LWH
V=8LWH

weight increases by 8 times
0.3 time s8=2.4

answer is 2.4lb

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2 years ago

Which inequality is true for x=5

Andreyy89

Answer:

The answer is A) 2x+ 5 > 13

Step-by-step explanation:

4 0

2 years ago

Clarke paid $5 each for three pairs of earrings. The tax rate was 7%. What is the amount Clarke paid?

Mrac [35]

Answer:

5 x 3 = 15

7% = 0.7 x 15 = 10.5

10.5 + 15 = 25.5

she paid $25.50

7 0

2 years ago

Read 2 more answers

Plz help<br>urgent !!!!<br>will give the brainliest !!

Mkey [24]

Answer:

$X = \begin{bmatrix}1&3\\ 2&4\end{bmatrix}$

Step-by-step explanation:

The question we have at hand is, in other words,

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}\left(X\right)=\begin{bmatrix}8&20\\ \:3&7\end{bmatrix}$ - where we have to solve for the value of $X$

If we have to isolate $X$ here, then we would have to take the inverse of the following matrix ...

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}$ ... so that it should be as follows ... $\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}^{-1}$

Therefore, we can conclude that the equation as to solve for " $X$ " will be the following,

$X=\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ - First find the 2 x 2 matrix inverse of the first portion,

$\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}$ = $\frac{1}{\det \begin{pmatrix}4&2\\ 1&1\end{pmatrix}}\begin{pmatrix}1&-2\\ -1&4\end{pmatrix}$ = $\frac{1}{2}\begin{bmatrix}1&-2\\ -1&4\end{bmatrix}$ = $\begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}$

At this point we have to multiply the rows of the first matrix by the rows of the second matrix,

$X = \begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ ,

$X = \begin{pmatrix}\frac{1}{2}\cdot \:8+\left(-1\right)\cdot \:3&\frac{1}{2}\cdot \:20+\left(-1\right)\cdot \:7\\ \left(-\frac{1}{2}\right)\cdot \:8+2\cdot \:3&\left(-\frac{1}{2}\right)\cdot \:20+2\cdot \:7\end{pmatrix}$ - Simplifying this, we should get ...

$\begin{bmatrix}1&3\\ 2&4\end{bmatrix}$ ... which is our solution.

7 0

2 years ago