The setup boxes in the synthetic division are (b)
<h3>How to determine the setup boxes?</h3>
The dividend is given as:
x^3 + 4x^2 + x - 6
The divisor is given as:
x - 2
Set the divisor to 0
x - 2 = 0
Solve for x
x = 2
Remove the variables in the dividend
1 + 4 + 1 - 6
Remove the arithmetic signs
1 4 1 - 6
So, the setup is:
2 | 1 4 1 - 6
Hence, the setup boxes are (b)
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Answer: 
<u>Switch operations</u>
Before: 
After:
Before you switch operation you remove the subtraction sign where -(16) is.
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<em>Hi there!</em>
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<em>1:10000 would be the scale.</em>
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Answer:
B. 1296 m^3
Step-by-step explanation:
To find the volume of a square pyramid, multiply the base by itself twice, then divide the height by 3. After getting both answers, multiply the answers.
In this case, the base is 18.
The height is 12.
First, we must multiply the base by itself twice.
18⋅18 = 324.
Next, divide the height by 3.
12/3 = 4.
Now that we have both answers, we multiply them.
324 ⋅ 4 = 1,296.
Therefore, 1,296 cm^3 is the volume of the square pyramid.
-9x=-36
divide both sides by -9
to get x by itself
to get +x
-9x/-9= -36/-9
cross out -9 and -9, then becomes -1*-1*x= x
x= -36/-9
answer:
x= 4
