2 years ago

HELP PLEASE!! what is the solution of the system ? y=-8x-2 and y=-6x+4

Mathematics

1 answer:

Illusion [34]2 years ago

5 0

Answer: -3

Since the both equal the same value we can combine the into -8x-2=-6x+4.

From there you can solve from whatever side you want, and the answer is -3.

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If ƒ(x ) = 3x + 1 and ƒ -1 = , then ƒ -1(7) =

Elden [556K]

F(x) = 3x + 1

let f(x) = y

y = 3x + 1

y - 1 = 3x

3x = y - 1

x = (y - 1)/3

From y = f(x), x = f⁻¹(y)

x = (y - 1)/3

f⁻¹(y) = (y - 1)/3

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f⁻¹(7) = 2

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X + 2y = 5 x - 3y = 7 What is the value of the y-determinant? -2 -1 2

grandymaker [24]

Answer:

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Step-by-step explanation:

Given the following system of equation:

x + 2y = 5
x - 3y = 7

Let's represent it using a matrix:

$\left[\begin{array}{ccc}1&2\\1&-3\end{array}\right] = \left[\begin{array}{ccc}5\\7\end{array}\right]$

The y‐numerator determinant is formed by taking the constant terms from the system and placing them in the y‐coefficient positions and retaining the x‐coefficients. Then:

$\left[\begin{array}{ccc}1&5\\1&7\end{array}\right]$

y-determinant = (1)(7) - (5)(1) = 2.

Therefore, the y-determinant = 2

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2 years ago

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3) 500
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Step-by-step explanation:

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