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2 years ago

A wire perpendicular to the screen carries a current in the direction shown.

Physics

2 answers:

mrs_skeptik [129]2 years ago

8 0

Answer:

A) Up

Explanation:

The direction of the current in the wire is going out of the screen. We can use the right-hand rule to find the direction of the magnetic field at point Z. In fact, we have to:

- Put the thumb of the right hand in the same direction as the current (out of the screen)

- Wrap the other fingers around the thumb. The direction of the fingers will be the same as the direction of the magnetic field.

By doing this procedure with out right hand, we see that the other fingers at point Z are directed up, so the magnetic field is also directed up.

____ [38]2 years ago

4 0

A) Up is the direction of the magnetic field at point Z.

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Answer:

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Time taken to make one oscillation, T = 0.25 s

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Frequency, f of oscillation is given as the reciprocal of time taken for one oscillation and is given by:

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A 15 kg bucket of water is suspended by a very light ropewrapped around a solid uniform cylinder 0.300 m in diamter withmass 12.

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Answer:

Part a)

$T = 42 N$

Part b)

$v_f = 11.8 m/s$

Part c)

$t = 1.7 s$

Part d)

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Explanation:

Part a)

While bucket is falling downwards we have force equation of the bucket given as

$mg - T = ma$

for uniform cylinder we will have

$TR = I\alpha$

so we have

$T = \frac{1}{2}MR^2(\frac{a}{R^2})$

$T = \frac{1}{2}Ma$

now we have

$mg = (\frac{M}{2} + m)a$

$a = \frac{mg}{(\frac{M}{2} + m)}$

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now we have

$T = \frac{12 \times 7}{2}$

$T = 42 N$

Part b)

speed of the bucket can be found using kinematics

so we have

$v_f^2 - v_i^2 = 2 a d$

$v_f^2 - 0 = 2(7)(10)$

$v_f = 11.8 m/s$

Part c)

now in order to find the time of fall we can use another equation

$v_f - v_i = at$

$11.8 - 0 = 7 t$

$t = 1.7 s$

Part d)

as we know that cylinder is at rest and not moving downwards

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$F = 42 + (12 \times 9.81)$

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