Given:
Equilateral Triangular Prism
Each side of the triangular face has a length of 196cm
The tent is 250cm long
I have attached an image of the tent. Since the height of the tent is also the height of the triangle, I will solve for the height of the triangle using Pythagorean theorem.
I divided the equilateral triangle into 2 right triangle. The height then becomes the long leg of the triangle. The hypotenuse is 196cm and the short leg is 98cm, half of one side of the triangle.
a² + b² = c²
a² = c² - b²
a² = (196cm)² - (98cm)²
a² = 38,416cm² - 9,604cm²
a² = 28,812cm²
a = √28,812cm²
a = 169.74cm
The height of the tent is 169.74 centimeters.
12. I need the graphs to answer it
11. y = 1/2x - 1
10. The first graph is the best
Answer:
the answer is 24
Step-by-step explanation:
applyourknowledge
That is a ratio. 7 x 3 = 21 and 13 x 3 = 39.
Step-by-step explanation:
because VW || YZ, the 2 triangles are similar.
this is given by the rules of equal angles of intersecting lines with parallel lines. Z to V and Y to W would be such intersecting lines.
and therefore, the angle at W is the angle at Y, the angle at V is the angle at Z. and therefore both angles at A are equal.
so, for similar triangles the scaling factor between corresponding pairs of sides is the same for all sides.
e.g. the same scaling factor that converts 7.2 to 12, converts then also x to x+4.
7.2 × f = 12
f = 12/7.2 = 12/ 72/10 = 120/72 = 10/6 = 5/3
x × 5/3 = x + 4
5x = 3x + 12
2x = 12
x = 6
A to Y = x = 6
W to A = x + 4 = 6 + 4 = 10