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2 years ago

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An object is acted upon by a force of 22 newtons to the right and a force of 13 newtons to the left. What is the magnitude and d

irection of the net force? A. 9 newtons to the right B. 9 newtons to the left C. 22 newtons to the right D. 35 newtons to the right E. 35 newtons to the left

2 answers:

Sedbober [7]2 years ago

8 0

Answer:

The answer is 9 Newtons to the right.

Explanation:

According to Newton's laws: The net force is the sum of all the forces acted upon the object or

Net force = ∑ of all forces.

In our problem we have two forces, one is going to the right and the other one goes to the left.

We are going to assume that the forces going to the right are positive and the forces to the left, negative.

Therefore the net force acting upon the object is:

Net force = 22 + (-13)

Net force = 22 - 13

Net force = 9 N.

As the force is positive, we can conclude that the force is going to the right.

Damm [24]2 years ago

6 0

9 Newtons on the right, because:

Right and left are opposite directions, however, in the same direction.

We know that, opposite directions, the signal is of subtraction. So, you need to make the difference between 22 and 13, you will see that it is 9. Therefore, the Resulting Force will be 9.

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A merry-go-round on a playground consists of a horizontal solid disk with a weight of 805 N and a radius of 1.58 m. A child appl

lozanna [386]

Answer:

The value is $KE = 259.6 \ J$

Explanation:

From the question we are told that

The weight of the horizontal solid disk is $W = 805 \ N$

The radius of the horizontal solid disk is $r = 1.58 \ m$

The force applied by the child is $F = 49.5 \ N$

The time considered is $t = 2.95 \ s$

Generally the mass of the horizontal solid disk is mathematically represented as

$m_h = \frac{W}{ g}$

=> $m_h = \frac{805}{ 9.8 }$

=> $m_h = 82.14 \ N$

Generally the moment of inertia of the horizontal solid disk is mathematically represented as

$I = \frac{1}{2} * m * r^ 2$

=> $I = \frac{1}{2} * 82.14 * 1.58^ 2$

=> $I = 102.5 \ kg \cdot m^2$

Generally the net torque experienced by the horizontal solid disk is mathematically represented as

$T = I * \alpha = F * r$

=> $\alpha = \frac{ F * r }{ I }$

=> $\alpha = \frac{ 49.5 * 1.58 }{ 102.53 }$

=> $\alpha = 0.7628$

Gnerally from kinematic equation we have that

$w = w_o + \alpha t$

Here $w_o$ is the initial angular velocity velocity of the horizontal solid disk which is $w_o = 0\ rad/s$

So

$w = 0 + 0.7628 * 2.95$

=> $w = 2.2503 \ rad/s$

Generally the kinetic energy is mathematically represented as

$KE = \frac{1}{2} * I * w^2$

=> $KE = \frac{1}{2} * 102.53 * 2.2503 ^2$

=> $KE = 259.6 \ J$

8 0

1 year ago

A rod of length 35.50 cm has linear density (mass per length) given by λ = 50.0 + 23.0x where x is the distance from one end, an

hram777 [196]

Answer:

(a)20.65g

(b)0.19m

Explanation:

(a) The total mass would be it's mass per length multiplied by the total lenght

0.355(50 + 23*0.355) = 20.65 g

(b) The center of mass would be at point c where the mass on the left and on the right of c is the same

Hence the mass on the left side would be half of its total mass which is 20.65/2 = 10.32 g

$c(50 + 23c) = 10.32$

$23c^2 + 50c - 10.32 = 0$

$c \approx 0.19m$

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What state of matter did the earth need to be in order for planetary differentiation to occur?

STatiana [176]

Gas. I know this because first you will need to do the equator so I will say gas

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The electric field strength E is measured as:

soldi70 [24.7K]

The correct answer is
<span>force per unit charge.

In fact, the electric field strength is defined as the electric force per unit charge experienced by a positive test charge located in the electric field. In formula:
</span> $E= \frac{F}{q}$
where
E is the electric field strength
F is the electric force experienced by the charge
q is the positive test charge.

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Vadim26 [7]

A)they can interbreed and produce fertile offsprings

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3 years ago

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