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2 years ago

Helpppp what is the area of the trapezoid? the diagram is not drawn to scale

Mathematics

1 answer:

lara [203]2 years ago

4 0

Answer:

Step-by-step explanation:

Google "Area of a trapezoid formula" and that will help you with this

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Write the standard form of the equation of the circle with its center at (-5,0) and a radius of 8 what is the equation of the ci

Leto [7]

Answer:

$\large\boxed{(x+5)^2+y^2=64}$

Step-by-step explanation:

The standard form of an equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the center (-5, 0) and the radius r = 8. Substitute:

$(x-(-5))^2+(y-0)^2=8^2\\\\(x+5)^2+y^2=64$

7 0

2 years ago

Which equation represents a linear function? (1 point)

Elan Coil [88]

Answer:

Option D

Step-by-step explanation:

' y = 4x − 1' would graph as a straight line. Therefore, it is a linear equation.

Liner equations are graphed as a straight line, while nonlinear equations are not.

4 0

2 years ago

1.34 x 1024 molecules of CH, is how many moles?

icang [17]

Answer:

1372.16

Step-by-step explanation:

If I am not mistaken, the answer is just 1.34*1024, which is 1372.16. Also, I assume that "moles" mean molecules.

3 0

2 years ago

What is the value of x? (x + 40) (3x) O 20 R O O 35 O O ASAP

Natasha2012 [34]

Angles TRS and VRW are vertical angles, so we can set them equal to each other to get x:

x+40=3x

40=2x

20=x

So the value of x is 20

3 0

2 years ago

How much money has to be invested at 5.9% interest compounded continuously to have $15,000 after 12 years?

scoray [572]

The amount of $7389.43 has to be invested at 5.9% interested continuously to have $15,000 after 12 years.

Step-by-step explanation:

The given is,

Future value, F = $15,000

Interest, i = 5.9%

( compounded continuously )

Period, t = 12 years

Step:1

Formula to calculate the present with compounded continuously,

$F=Pe^{(i)(t)}$ ...............(1)

Substitute the values in equation (1) to find the P value,

$15000=Pe^{(0.059)(12)}$ ( ∵ $i = \frac{5.9}{100}=0.059$ )

$15000=Pe^{0.708}$

$15000=P(2.0299)$ ( ∵ $e^{o.708} =2.0299$ )

We change the P (Present value) into the left side,

$P=\frac{15000}{2.0299}$

$=7389.427$

≅ 7389.43

P = $ 7389.43

Result:

The amount of $7389.43 has to be invested at 5.9% interested continuously to have $15,000 after 12 years.

8 0

2 years ago