All categories

2 years ago

The image of parallelogram PQRS after a reflection across Line W Y is parallelogram P'Q'R'S'.

Mathematics

2 answers:

GenaCL600 [577]2 years ago

5 0

Answer:

Step-by-step explanation:

Let line WY be the line of reflection

RR has the midpoint at Z.

In other words, the line: $RZ$ = $\frac{1}{2}RR$

SS is another line

It has a midpoint at X. In other words, line SX = $\frac{1}{2} SS$

If SS = 12, then the line SX = $\frac{1}{2} (12)\\ = 6$

Because the shape is a parallelogram, it means that RZ = SX = 6

Luden [163]2 years ago

3 0

Answer:

the answer is 6

Step-by-step explanation:

You might be interested in

Which table correctly shows all the sample spaces for tossing a coin and rolling an odd number on a six-sided number cube? Coin

Sati [7]

Table D I believe :) Hope this helps!!

5 0

2 years ago

Read 2 more answers

Write in simplest form 1/3 times 1 1/3

IRINA_888 [86]

Answer:

3 2/3

Step-by-step explanation:

Use a calculator please

8 0

2 years ago

More than $70 billion is spent each year in the drive-thru lanes of America’s fast-food restaurants. Having quick, accurate, and

artcher [175]

Answer:

a) There is no significant difference between restaurants with and without order-confirmation boards

b) -12.5 ± 3.604 or C.1.E (-16.10, -8.90)

Step-by-step explanation:

answers are in the attachment below

8 0

2 years ago

If y varies directly with x. and y=10 when x=5.6, find the value of y when<br> X=3

Nady [450]

Answer: 5.3571

Step-by-step explanation:

The formula used to calculate direct proportion is: y = kx

We will find the constant of proportionality when y=10 and x=5.6. This will be:

y = kx

10 = 5.6k

k = 10/5.6

k = 1.7857143

The value of y when X=3 will be:

y = kx

y = 1.7857143 × 3

y = 5.3571

3 0

2 years ago

How to show these 2 problems are inverses

nataly862011 [7]

$\bf \begin{cases}
f(x)=\sqrt[3]{7x-2}\\\\
g(x)=\cfrac{x^3+2}{7}
\end{cases}\\\\
-----------------------------\\\\
now
\\\\
f[\ g(x)\ ]\implies f\left[ \frac{x^3+2}{7} \right]\implies \sqrt[3]{7\left[ \frac{x^3+2}{7} \right]-2}\implies \sqrt[3]{x^3+2-2}
\\\\\\
\sqrt[3]{x^3}\implies x\\\\
-----------------------------\\\\
or
\\\\
g[\ f(x)\ ]\implies g\left[\sqrt[3]{7x-2}\right]\implies \cfrac{\left[\sqrt[3]{7x-2}\right]^3+2}{7}
\\\\\\
\cfrac{7x-2+2}{7}\implies \cfrac{7x}{7}\implies x$

thus f[ g(x) ] = x indeed, or g[ f(x) ] =x, thus they're indeed inverse of each other

8 0

2 years ago