Q1. The answer is 1.
It can be calculated using the equation:
(1/2)ⁿ = x
x - decimal amount remaining,
n - a number of half-lives.
x = 50% = 50/100 = 0.5
n = ?
(1/2)ⁿ = 0.5
log((1/2)ⁿ) = log(0.5)
n * log(1/2) = log(0.5)
n * log(0.5) = log(0.5)
n = log(0.5)/log(0.5)
n = 1
Q10. The answer is 2.
It can be calculated using the equation:
(1/2)ⁿ = x
x - decimal amount remaining,
n - a number of half-lives.
Rhyolite #2 has 25% of the parent H remaining:
x = 25% = 25/100 = 0.25
n = ?
(1/2)ⁿ = 0.25
log((1/2)ⁿ) = log(0.25)
n * log(1/2) = log(0.25)
n * log(0.5) = log(0.25)
n = log(0.25)/log(0.5)
n = -0.602 / - 0.301
n = 2
Q3. The answer is 100 million years.
A number of half-lives (n) is a quotient of total time elapsed (t) and length of half-life (H):
n = t/H
n = 1
t = ?
H = 100 000 000 years
n = t/H
t = n * H
t = 1 * 100 000 000 years
t = 100 000 000 years<span>
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A large deposit of sand and soil formed at the end of a river is a delta. When a river empties into the ocean, the current carrying smaller particles, such as soil and sand, slows down and eventually stops, causing these particles to be dropped off on the shore. This eventually leads to a triangular deposit, usually referred to as the mouth of the river.
Answer:
d. 28,650 years
Explanation:
Since 14C has a single half-life of 5,730 years
The number of years that is going to make up 5 half-lives for 14C will be;
5,730 years × 5 = 28,650 years
Answer:
Cytokinesis
Explanation:
Cytokinesis is similar to telophase. The cell devides it cytoplasm into two pieces which creates two daughter cells.
