Answer:
37.27% probability that he or she will have a heart attack.
Step-by-step explanation:
Bayes Theorem:
Two events, A and B.
In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
In this question:
Event A: Periodontal disease
Event B: Heart attack
Researchers discovered that 82% of people who have suffered a heart attack had periodontal disease, an inflammation of the gums.
This means that
Only 33% of healthy people have this disease.
This means that
Suppose that in a certain community heart attacks are quite rare, occurring with only 15% probability.
This means that
If someone has periodontal disease, what is the probability that he or she will have a heart attack
37.27% probability that he or she will have a heart attack.
#2 #3 and #5 I think but I could be wrong. Good luck!
For number 3, it is reciprocal
and for number 4, it is whole number
First, make an organized list of the factors for each number. The common factors are 1, 2, 4, 8, and 16, and the greatest of these is 16. So, the greatest common factor or GCF of 48 and 64 is 16.