How do you want me to give you points tell me and I’ll do it
Answer:
the filling stops when the pressure of the pump equals the pressure of the interior air plus the pressure of the walls.
Explanation:
This exercise asks to describe the inflation situation of a spherical fultball.
Initially the balloon is deflated, therefore the internal pressure is equal to the pressure of the air outside, atmospheric pressure, when it begins to inflate the balloon with a pump this creates a pressure in the inlet valve and as it is greater than the pressure inside, the air enters it, this is repeated in each filling cycle, manual pump.
When the ball is full we have two forces, the one created by the external walls and the one aired by the pressure of the pump, these forces are directed towards the inside, but the air molecules exert a pressure towards the outside, which translates into a force. When these two forces are equal, the pump is no longer able to continue introducing air into the balloon.
Consequently the filling stops when the pressure of the pump equals the pressure of the interior air plus the pressure of the walls.
There's a short handy formula for that.
If the object is just dropped and not tossed, and it's not affected by air resistance on the way down, then the distance it falls in T seconds is
D = (1/2) (gravity) (T²)
For this problem . . .
176.4 m = (1/2) (9.8 m/s²) (T²)
Divide each side by (4.9 m/s²) :
T² = (176.4 m) / (4.9 m/s²)
T² = (36 s²)
Take the square root of each side:
<em>T = 6 seconds</em>
I would say that B seems more accurate because rhythm and tone seems like a poem
Answer:
u= 200 m/s
Explanation:
Given that
Mass of bullet ,m= 50 gm
Assume that mass of block ,M= 1.2 kg
Lets take speed of the bullet before collision = u m/s
The speed of the system after collision ,v= 8 m/s
There is no any external force ,that is why linear momentum of the system will be conserve.
Linear momentum ,P = mass x velocity
m u = (M+m)v
0.05 x u = (1.2 + 0.05 ) x 8
u= 200 m/s
Therefore the speed of the bullet just before the collision is 200 m/s.
