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2 years ago

13

What step should you perform to bisect an angle drawn on tracing paper

2 answers:

max2010maxim [7]2 years ago

8 0

Answer:

Step-by-step explanation:

• Suppose the angle is PQR where Q is the midpoint.

• Keep the compass at angle vertex Q and adjust some wide setting (the width is not important).

• Without changing the compass, draw an arc across each leg of the angle

• Now keep the compasses on the point drawn on each leg, and draw an arc in the interior of the angle.

• Using a ruler, draw a line through the vertex to the point where the arcs cross

nikitadnepr [17]2 years ago

3 0

Answer: fold the paper through the vertex so that the rays lie on top of each other.

Step-by-step explanation: apex

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The graph shows the total monthly sales as a function of the number of cake tiers. Which statement is true?

liraira [26]

as tiers increases, sales increases

since there seems to be no assemtote (horizontal or vertical), As the number of cake tiers increases without bound, the total monthly sales increase without bound.

answer is 3rd option

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2 years ago

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Find the 50th term of 6,12,18,24

Ilia_Sergeevich [38]

Answer:

300

Step-by-step explanation:

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1 year ago

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If you read 4/9 of a page in 3/5 minutes what’s your unit rate page per minute

Vikentia [17]

Answer:

12/45

Step-by-step explanation:

The unit rate is 12/45, because 4 times 3 is 12, and 9 times 5 is 45.

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2 years ago

The distance from Kenya's house to her job is 18 miles. One morning she left her house at 7:15 a.m. She traveled at the rate of

Snezhnost [94]

20 minutes = 1/3 of an hour

1/3 = 0.333

1/3 x 45mph = 15, so she drove 15 miles at 45mph

18-15 = 3

3 miles/ 20 mph = 0.15 hours

0.333+0.15 = 0.483 hours total

0.483 x 60 = 28.98 so approximately 29 minutes total driving time

7:15 + 29 minutes is 7:44 am she arrived at work

8 0

2 years ago

A box with a rectangular base and open top must have a volume of 128 f t 3 . The length of the base is twice the width of base.

noname [10]

Answer:

$Width = 4ft$

$Height = 4ft$

$Length = 8ft$

Step-by-step explanation:

Given

$Volume = 128ft^3$

$L = 2W$

$Base\ Cost = \$9/ft^2$

$Sides\ Cost = \$6/ft^2$

Required

The dimension that minimizes the cost

The volume is:

$Volume = LWH$

This gives:

$128 = LWH$

Substitute $L = 2W$

$128 = 2W * WH$

$128 = 2W^2H$

Make H the subject

$H = \frac{128}{2W^2}$

$H = \frac{64}{W^2}$

The surface area is:

Area = Area of Bottom + Area of Sides

So, we have:

$A = LW + 2(WH + LH)$

The cost is:

$Cost = 9 * LW + 6 * 2(WH + LH)$

$Cost = 9 * LW + 12(WH + LH)$

$Cost = 9 * LW + 12H(W + L)$

Substitute: $H = \frac{64}{W^2}$ and $L = 2W$

$Cost =9*2W*W + 12 * \frac{64}{W^2}(W + 2W)$

$Cost =18W^2 + \frac{768}{W^2}*3W$

$Cost =18W^2 + \frac{2304}{W}$

To minimize the cost, we differentiate

$C' =2*18W + -1 * 2304W^{-2}$

Then set to 0

$2*18W + -1 * 2304W^{-2} =0$

$36W - 2304W^{-2} =0$

Rewrite as:

$36W = 2304W^{-2}$

Divide both sides by W

$36 = 2304W^{-3}$

Rewrite as:

$36 = \frac{2304}{W^3}$

Solve for $W^3$

$W^3 = \frac{2304}{36}$

$W^3 = 64$

Take cube roots

$W = 4$

Recall that:

$L = 2W$

$L = 2 * 4$

$L = 8$

$H = \frac{64}{W^2}$

$H = \frac{64}{4^2}$

$H = \frac{64}{16}$

$H = 4$

Hence, the dimension that minimizes the cost is:

$Width = 4ft$

$Height = 4ft$

$Length = 8ft$

8 0

2 years ago