Answer:
an = -6 + n
a10 = -6+ 10 =4
Step-by-step explanation:
an should start at one behind the first number so it should be -6. Then we add whatever the sequence is increasing by, which is 1 in this case, multiplied by n.
an = -6 + n
a10 = -6+ 10 =4
Step-by-step explanation:
2x + 100 = 90
x = -5
Angle A = 45 - 5 = 40.
Answer/Step-by-step explanation:
27.
✔️Sin 23 = opp/hyp
Sin 23 = t/34
34*sin 23 = t
t = 13.3
✔️Cos 23 = adj/hyp
Cos 23 = s/34
s = 34*cos 23
s = 31.3
28.
✔️Sin 36 = opp/hyp
Sin 36 = s/5
s = 5*sin 36
s = 2.9
✔️Cos 36 = adj/hyp
Cos 36 = r/5
r = 5*cos 36
r = 4.0
29.
✔️Sin 70 = opp/hyp
Sin 70 = w/10
w = 10*sin 70
w = 9.4
✔️Cos 70 = adj/hyp
Cos 70 = v/10
v = 10*cos 70
v = 3.4
Answer:
Step-by-step explanation:
Answer:
We can see that this is dependent probability. We can find dependent probability of happening event A then event B by multiplying probability of event A by probability of event B given that event A already happened.
Step-by-step explanation:
In our case event A is pirate hitting captain's ship and event B is captain missing pirate's ship. We have been given that pirate shoots first so pirate's ship can't be hit before pirate shoots his cannons. So probability of hitting captain's ship is 1/3. We have been given that if Captain Ben's ship is already hit then Captain Ben will always miss. So the probability of Captain missing the dread pirate's ship given the pirate Luis hitting the Captain ship is 1. Now to find probability that pirate hits Captain, but Captain misses we will multiply our both probabilities.
