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2 years ago

Find the equation of the line

Mathematics

2 answers:

kotegsom [21]2 years ago

7 0

Of the line of what?

Elina [12.6K]2 years ago

3 0

The equation is y = -3x + 5

Slope intercept form is y = mx + b, in this equation m = -3

-3(3) + 5 =
-9 + 5 =
-4
By plugging in the x coordinate it shows the line goes through (3, -4)

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Calculate: 3400*6 1/2 *1/100

marishachu [46]

questions clear likhh

thank for extra points

7 0

2 years ago

Use the linear combination method to solve the system of equations. Explain each step of your solution. 2x-3y=13 4x-y=-9

Tems11 [23]

2x -3y = 13

4x -y = -9

Multiply the second equation by -3 to make the coefficient of Y opposite the first equation.

4x -y = -9 x -3 = -12x + 3y = 27

Now add this to the first equation:

2x -12x = -10x

-3y +3y = 0

13 +27 = 40

Now you have :

-10x = 40

Divide each side by -10:

x = 40 / -10

x = -4

Now you have a value for x, replace that into the first equation and solve for y:

2(-4) - 3y = 13

-8 - 3y = 13

Add 8 to both sides:

-3y = 21

Divide both sides by -3:

y = 21/-3

y = -7

Now you have X = -4 and y = -7

(-4,-7)

3 0

2 years ago

Three friends go to the movies. Each ticket costs $7. They also buy popcorn for $6, candy for $4 and a drink for $2. The friends

ozzi

Each friend owes 11 dollars
((7*3)+4+2+6)/3=11

6 0

2 years ago

Read 2 more answers

The total cost of an order of gift baskets includes the cost of each gift basket plus a one time delivery fee. The cost of each

Helen [10]

Answer:

x = cost of each gift basket = $14.5

y = one time delivery fee = $135

Step-by-step explanation:

Let

x = cost of each gift basket

y = one time delivery fee

40x + y = 715 (1)

400x + y = 5935 (2)

Subtract (1) from (2)

400x - 40x = 5935 - 715

360x = 5220

x = 5220/360

x = 14.5

Substitute x = 14.5 into (1)

40x + y = 715 (1)

40(14.5) + y = 715

580 + y = 715

y = 715 - 580

y = 135

x = cost of each gift basket = $14.5

y = one time delivery fee = $135

4 0

2 years ago

Find a cubic function with the given zeros.

Fed [463]

Answer:

The correct option is D) $f(x) = x^3 + 2x^2 - 2x - 4$ .

Step-by-step explanation:

Consider the provided cubic function.

We need to find the equation having zeros: Square root of two, negative Square root of two, and -2.

A "zero" of a given function is an input value that produces an output of 0.

Substitute the value of zeros in the provided options to check.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x + 4$ .

$f(x) = x^3 + 2x^2 - 2x + 4\\f(x) = (-2)^3 + 2(-2)^2 - 2(-2) + 4\\f(x) =-8 + 2(4)+4 + 4\\f(x) =8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 + 2x - 4$ .

$f(x) = x^3 + 2x^2 + 2x - 4\\f(x) = (-2)^3 + 2(-2)^2 + 2(-2) - 4\\f(x) =-8+2(4)-4-4\\f(x) =-8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 - 2x^2 - 2x - 4$ .

$f(x) = x^3 - 2x^2 - 2x - 4\\f(x) = (-2)^3 - 2(-2)^2 - 2(-2) - 4\\f(x) =-8-8+4-4\\f(x) =-16$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-2)^3+2(-2)^2 - 2(-2) - 4\\f(x) =-8+8+4-4\\f(x) =0$

Now check for other roots as well.

Substitute x=√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (\sqrt{2})^3+2(\sqrt{2})^2 - 2(\sqrt{2}) - 4\\f(x) =2\sqrt{2}+4-2\sqrt{2}-4\\f(x) =0$

Substitute x=-√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-\sqrt{2})^3+2(-\sqrt{2})^2 - 2(-\sqrt{2}) - 4\\f(x) =-2\sqrt{2}+4+2\sqrt{2}-4\\f(x) =0$

Therefore, the option is correct.

8 0

2 years ago